For the combustion of $1 \ mol$ of liquid benzene at $298 \ K$,the heat of reaction at constant pressure is $-3268 \ kJ \ mol^{-1}$. What is the heat of combustion at constant volume? $(R = 8.314 \times 10^{-3} \ kJ \ K^{-1} \ mol^{-1})$

  • A
    $-3264.2 \ kJ \ mol^{-1}$
  • B
    $-1632 \ kJ \ mol^{-1}$
  • C
    $-6728 \ kJ \ mol^{-1}$
  • D
    $-672.8 \ kJ \ mol^{-1}$

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Similar Questions

At $300 \, K$ temperature,the standard heat of formation of benzoic acid $(s)$,$CO_{2(g)}$,and $H_2O_{(l)}$ are $-408$,$-393$,and $-286 \, kJ \, mol^{-1}$ respectively. At constant pressure,the heat of combustion for benzoic acid will be $..... \, kJ$.

For the reaction $2H_{(g)} \to H_{2(g)}$,the signs of $\Delta H$ and $\Delta S$ are:

Match the following processes with their corresponding entropy changes:
Process Entropy Change
$(a)$ Liquid to vapor conversion $(1)$ $\Delta S = 0$
$(b)$ Process not spontaneous at any temperature $(2)$ $\Delta S = (+)$
$(c)$ Reversible expansion of an ideal gas $(3)$ $\Delta S = (-)$

The molar heat of neutralization of $NaOH$ with $HCl$ in comparison to that of $KOH$ with $HNO_3$ is:

For the reaction $2X_{(g)} + Y_{(g)} \to 2Z_{(g)}$ at $298 \ K$,$\Delta U = -10.5 \ kJ$ and $\Delta S^o = -10.5 \ J/K$. Calculate $\Delta G^o$ for the reaction. Will the reaction be spontaneous or not? Explain.

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