For the complex ion [Ni(Cl)_4]^{2-}, what is | vedclass

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(B) $1$. In the complex ion $[Ni(Cl)_4]^{2-}$, the oxidation state of $Ni$ is $+2$. $2$. The electronic configuration of $Ni^{2+}$ $(Z=28)$ is $[Ar] 3

Vedclass · Accepted Answer

$2.83$

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(B) $1$. In the complex ion $[Ni(Cl)_4]^{2-}$, the oxidation state of $Ni$ is $+2$. $2$. The electronic configuration of $Ni^{2+}$ $(Z=28)$ is $[Ar] 3d^8$. $3$. Since $Cl^-$ is a weak field ligand, it does not cause pairing of electrons in the $3d$ orbitals. $4$. The $3d^8$ configuration has two unpaired electrons $(n=2)$. $5$. The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$. $6$. Substituting $n=2$, we get $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \ BM$.

For the complex ion $[Ni(Cl)_4]^{2-}$, what is the theoretical value of the magnetic moment (in $BM$)?

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