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(C) At equilibrium,the rate of the forward reaction $(r_f)$ becomes equal to the rate of the reverse reaction $(r_b)$.Initially,the rate of the forwar

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(C) At equilibrium,the rate of the forward reaction $(r_f)$ becomes equal to the rate of the reverse reaction $(r_b)$.Initially,the rate of the forward reaction is maximum and decreases with time as the concentration of reactant $A$ decreases.Conversely,the rate of the reverse reaction is zero initially and increases with time as the concentration of product $B$ increases.At equilibrium,both rates become constant and equal to each other.This is correctly represented by graph $C$.

For the equilibrium $A \rightleftharpoons B$,the variation of the rate of the forward $(a)$ and reverse $(b)$ reaction with time is given by:

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