For the following three reactions a, b and c, | vedclass

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Question

(C) Given reactions are:$(i)$ $CO_{(g)} + H_2O_{(g)} \rightleftharpoons CO_{2(g)} + H_{2(g)}$ ; $K_1$$(ii)$ $CH_{4(g)} + H_2O_{(g)} \rightleftharpoons

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$K_3 = K_1 \cdot K_2$

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(C) Given reactions are:$(i)$ $CO_{(g)} + H_2O_{(g)} \rightleftharpoons CO_{2(g)} + H_{2(g)}$ ; $K_1$$(ii)$ $CH_{4(g)} + H_2O_{(g)} \rightleftharpoons CO_{(g)} + 3H_{2(g)}$ ; $K_2$Adding reaction $(i)$ and $(ii)$:$(CO_{(g)} + H_2O_{(g)}) + (CH_{4(g)} + H_2O_{(g)}) \rightleftharpoons (CO_{2(g)} + H_{2(g)}) + (CO_{(g)} + 3H_{2(g)})$Canceling $CO_{(g)}$ from both sides:$CH_{4(g)} + 2H_2O_{(g)} \rightleftharpoons CO_{2(g)} + 4H_{2(g)}$This is reaction $(iii)$.When reactions are added,their equilibrium constants are multiplied.Therefore,$K_3 = K_1 \cdot K_2$.

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