(A) In circuit $(A)$,the impedance is $Z_A = R = 40 \ \Omega$.In circuit $(B)$,the impedance is $Z_B = \sqrt{R^2 + (X_L - X_C)^2}$.Since $Z_B = \sqrt{

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The r.m.s. current in circuit $(B)$ can never be greater than that in circuit $(A)$.

(A) In circuit $(A)$,the impedance is $Z_A = R = 40 \ \Omega$.In circuit $(B)$,the impedance is $Z_B = \sqrt{R^2 + (X_L - X_C)^2}$.Since $Z_B = \sqrt{R^2 + (X_L - X_C)^2} \ge R$,it follows that $Z_B \ge Z_A$.The r.m.s. current is given by $I = V/Z$. Since the voltage $V$ is the same $(220 \ V)$ for both circuits,$I_B = V/Z_B$ and $I_A = V/Z_A$.Since $Z_B \ge Z_A$,it implies $I_B \le I_A$. Thus,the r.m.s. current in circuit $(B)$ can never be greater than that in circuit $(A)$.

Class 12 Physics Alternating Current Inductance, Capacitance and Resistance in Series and Parallel

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For the given figure,choose the correct option.

MHT CET 2024 All MHT CET

A
The r.m.s. current in circuit $(B)$ can never be greater than that in circuit $(A)$.
B
The r.m.s. current in circuit $(A)$ is always equal to that in circuit $(B)$.
C
The r.m.s. current in circuit $(B)$ can be greater than in circuit $(A)$.
D
At resonance,current in $(B)$ is less than that in circuit $(A)$.

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Alternating Current

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Inductance, Capacitance and Resistance in Series and Parallel

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