For the given uniform square lamina ABCD whos | vedclass

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(A) The center of mass of a uniform lamina lies at its geometric center. When a portion of the lamina is removed,the new center of mass shifts away fr

Vedclass · Accepted Answer

If part $OCD$ is removed,the center of mass $(COM)$ will shift towards $E$,on line $OE$.

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(A) The center of mass of a uniform lamina lies at its geometric center. When a portion of the lamina is removed,the new center of mass shifts away from the center of mass of the removed portion along the line connecting the original center of mass and the center of mass of the removed portion.$A$: Removing triangle $OCD$ (center of mass at distance $d$ from $O$ along $OH$): The $COM$ shifts away from the center of mass of $OCD$. Since $OCD$ is below $O$,the $COM$ shifts upwards towards $F$,not $E$. This statement is incorrect.$B$: Removing rectangle $FHDC$ (center of mass at distance $d'$ from $O$ along $OH$): The $COM$ shifts away from the center of mass of $FHDC$. Since $FHDC$ is below $O$,the $COM$ shifts upwards towards $F$,not $E$. This statement is incorrect.$C$: Removing triangle $HOG$ (center of mass in the fourth quadrant): The $COM$ shifts away from the center of mass of $HOG$ towards the second quadrant (towards $B$). This is correct.$D$: Removing rectangle $EGDA$ (center of mass in the third quadrant): The $COM$ shifts away from the center of mass of $EGDA$ towards the first quadrant (towards $C$). This statement is incorrect.Note: Given the options,$A$ and $B$ are clearly incorrect. In many standard versions of this problem,the intended incorrect statement is $A$ or $B$ depending on the specific geometry. Based on standard physics principles,$A$ is incorrect.

For the given uniform square lamina $ABCD$ whose centre is $O$,pick the incorrect statement.

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