For the identification of beta-naphthol using | vedclass

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Question

(D) In the dye test,the phenolic $-OH$ group is converted to the phenoxide ion $-O^{\ominus}$ in the presence of a base.This phenoxide ion is a strong

Vedclass · Accepted Answer

alkaline solution of $\beta$-naphthol.

Vedclass · Answer

(D) In the dye test,the phenolic $-OH$ group is converted to the phenoxide ion $-O^{\ominus}$ in the presence of a base.This phenoxide ion is a strong activating group that increases the electron density on the aromatic ring,thereby facilitating Electrophilic Aromatic Substitution $(EAS)$ with the diazonium salt.This activation is only possible in an alkaline solution.Therefore,the correct option is $(D)$.

For the identification of $\beta$-naphthol using dye test,it is necessary to use :

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