For the reaction, 3A + 2B to C + D, the diffe | vedclass

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Question

(A) For a general reaction $aA + bB 	o cC + dD$, the rate of reaction is expressed as:Rate $= -\frac{1}{a} \frac{d[A]}{dt} = -\frac{1}{b} \frac{d[B]}

Vedclass · Accepted Answer

$-\frac{1}{3} \frac{d[A]}{dt} = \frac{d[C]}{dt} = k[A]^n[B]^m$

Vedclass · Answer

(A) For a general reaction $aA + bB 	o cC + dD$, the rate of reaction is expressed as:Rate $= -\frac{1}{a} \frac{d[A]}{dt} = -\frac{1}{b} \frac{d[B]}{dt} = \frac{1}{c} \frac{d[C]}{dt} = \frac{1}{d} \frac{d[D]}{dt} = k[A]^n[B]^m$Given the reaction $3A + 2B 	o C + D$, the rate expression is:Rate $= -\frac{1}{3} \frac{d[A]}{dt} = -\frac{1}{2} \frac{d[B]}{dt} = \frac{d[C]}{dt} = \frac{d[D]}{dt} = k[A]^n[B]^m$Comparing this with the given options, the correct representation is $-\frac{1}{3} \frac{d[A]}{dt} = \frac{d[C]}{dt} = k[A]^n[B]^m$.

For the reaction, $3A + 2B \to C + D$, the differential rate law can be written as:

Similar Questions

In the reaction $2SO_3 \to 2SO_2 + O_2$,initially $40 \ g$ of $SO_3$ is heated in a $100 \ mL$ container. If after $10 \ min$,$3.2 \ g$ of $O_2$ is formed,find the rate of reaction in $mol \ L^{-1} \ min^{-1}$.

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Which of the following statements is correct?

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