For the reaction: N_{2(g)} + 3H_{2(g)} righta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Calculate moles of reactants: Moles of $N_2 = \frac{168 \ 	ext{g}}{28 \ 	ext{g/mol}} = 6 \ 	ext{mol}$. Moles of $H_2 = \frac{30 \ 	ext{g}

Vedclass · Accepted Answer

$-106$

Vedclass · Answer

(A) $1$. Calculate moles of reactants: Moles of $N_2 = \frac{168 \ 	ext{g}}{28 \ 	ext{g/mol}} = 6 \ 	ext{mol}$. Moles of $H_2 = \frac{30 \ 	ext{g}}{2 \ 	ext{g/mol}} = 15 \ 	ext{mol}$.$2$. Identify limiting reagent: According to the stoichiometry $N_2 + 3H_2 ightarrow 2NH_3$,$1 \ 	ext{mol}$ of $N_2$ requires $3 \ 	ext{mol}$ of $H_2$. For $6 \ 	ext{mol}$ of $N_2$,we need $18 \ 	ext{mol}$ of $H_2$. Since we only have $15 \ 	ext{mol}$ of $H_2$,$H_2$ is the limiting reagent.$3$. Calculate moles of $NH_3$ produced: $3 \ 	ext{mol}$ of $H_2$ produce $2 \ 	ext{mol}$ of $NH_3$. Thus,$15 \ 	ext{mol}$ of $H_2$ produce $\frac{2}{3} 	imes 15 = 10 \ 	ext{mol}$ of $NH_3$.$4$. Calculate $\Delta n_g$: $\Delta n_g = \sum n_p - \sum n_r = 10 - (5 + 15) = -10 \ 	ext{mol}$ for the actual reaction occurring.$5$. Calculate $\Delta U$: $\Delta U = \Delta H - \Delta n_g RT$. Given $\Delta H$ for $2 \ 	ext{mol}$ of $NH_3$ is $-24 \ 	ext{kcal}$,for $10 \ 	ext{mol}$ it is $-24 	imes 5 = -120 \ 	ext{kcal}$.$6$. $\Delta U = -120 - (-10 	imes 0.002 \ 	ext{kcal/mol K} 	imes 700 \ 	ext{K}) = -120 + 14 = -106 \ 	ext{kcal}$.

Column-$I$	Column-$II$
$A$. $5.6 \ L$ of $SO_{2(g)}$ at $STP$	$I$. $32 \ g$
$B$. $1.2 \times 10^{24}$ atoms of oxygen	$II$. $66 \ g$
$C$. $33.6 \ L$ of $CO_{2(g)}$ at $STP$	$III$. $42 \ g$
$D$. $1.5 \ g$-molecule of $N_2$	$IV$. $16 \ g$

Similar Questions

$A$ photon having a wavelength of $310 \ nm$ is used to break the bond of an $A_2$ molecule with a bond energy of $288 \ kJ \ mol^{-1}$. Calculate the percentage of the photon's energy that is converted into kinetic energy $(K.E.)$. [Given: $hc = 12400 \ eV \mathring{A}$,$1 \ eV/atom = 96 \ kJ/mol$]

Match the following:

Column-$I$ Column-$II$

$A$. $5.6 \ L$ of $SO_{2(g)}$ at $STP$ $I$. $32 \ g$

$B$. $1.2 \times 10^{24}$ atoms of oxygen $II$. $66 \ g$

$C$. $33.6 \ L$ of $CO_{2(g)}$ at $STP$ $III$. $42 \ g$

$D$. $1.5 \ g$-molecule of $N_2$ $IV$. $16 \ g$

The correct match is:

Which of the following statements is incorrect for the compound $A_xB_y$?

Which of the following has the least mass?

Which of the following contain the same number of atoms?
$A$. $2 \text{ g}$ of $O_2$ gas
$B$. $4 \text{ g}$ of $SO_2$ gas
$C$. $1400 \text{ mL}$ of $O_2$ at $STP$
$D$. $0.05 \text{ L}$ of $He$ at $STP$
$E$. $0.0625 \text{ mol}$ of $H_2$ gas
Choose the correct answer from the options given below:

Vedclass Test Series

Exam Paper Generator

Online Exam Module