For the reaction N_{2(g)} + O_{2(g)} rightlef | vedclass

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(B) For the reaction: $N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$Initial concentration $(t=0)$: $1 \ M$ of $N_2$,$1 \ M$ of $O_2$,$0 \ M$ of $N

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$\frac{1}{1 + \sqrt{2}}$

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(B) For the reaction: $N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$Initial concentration $(t=0)$: $1 \ M$ of $N_2$,$1 \ M$ of $O_2$,$0 \ M$ of $NO$.At equilibrium $(t=eq)$: $(1-\alpha) \ M$ of $N_2$,$(1-\alpha) \ M$ of $O_2$,$2\alpha \ M$ of $NO$.$K_C = \frac{[NO]^2}{[N_2][O_2]} = \frac{(2\alpha)^2}{(1-\alpha)(1-\alpha)} = \frac{(2\alpha)^2}{(1-\alpha)^2} = 2$.Taking the square root on both sides: $\sqrt{2} = \frac{2\alpha}{1-\alpha}$.$\sqrt{2}(1-\alpha) = 2\alpha$.$\sqrt{2} - \sqrt{2}\alpha = 2\alpha$.$\sqrt{2} = \alpha(2 + \sqrt{2})$.$\alpha = \frac{\sqrt{2}}{2 + \sqrt{2}} = \frac{\sqrt{2}}{\sqrt{2}(\sqrt{2} + 1)} = \frac{1}{\sqrt{2} + 1}$.

For the reaction $N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$; if $K_C = 2$,then the degree of dissociation of $O_2$ is:

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