For the reaction,2Cl_{(g)} to Cl_{2_{(g)}},wh | vedclass

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(B) The reaction is $2Cl_{(g)} 	o Cl_{2_{(g)}}$.$1$. $\Delta H$: Bond formation is an exothermic process,meaning energy is released. Therefore,$\Delt

Vedclass · Accepted Answer

$\Delta H < 0, \Delta S < 0$

Vedclass · Answer

(B) The reaction is $2Cl_{(g)} 	o Cl_{2_{(g)}}$.$1$. $\Delta H$: Bond formation is an exothermic process,meaning energy is released. Therefore,$\Delta H $2$. $\Delta S$: The reaction involves the conversion of $2 	ext{ moles}$ of gaseous atoms into $1 	ext{ mole}$ of a gaseous molecule. Since the number of moles of gas decreases,the randomness or disorder of the system decreases. Therefore,$\Delta S < 0$ (negative).

For the reaction,$2Cl_{(g)} \to Cl_{2_{(g)}}$,what are the signs of $\Delta H$ and $\Delta S$?

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