For the reaction $R \rightarrow P$,the concentration of a reactant changes from $0.03 \, M$ to $0.02 \, M$ in $25 \, minutes$. Calculate the average rate of reaction using units of time both in $minutes$ and $seconds$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
The average rate of reaction is given by the formula: $\text{Average rate} = -\frac{\Delta[R]}{\Delta t}$
Substituting the given values:
$\text{Average rate} = -\frac{[R]_2 - [R]_1}{t_2 - t_1} = -\frac{0.02 \, M - 0.03 \, M}{25 \, min} = -\frac{-0.01 \, M}{25 \, min} = 4 \times 10^{-4} \, M \, min^{-1}$
To convert the rate into $seconds^{-1}$:
$\text{Average rate} = \frac{4 \times 10^{-4} \, M}{60 \, s} = 6.67 \times 10^{-6} \, M \, s^{-1}$

Explore More

Similar Questions

Find the average rate of formation of $O_{2(g)}$ in the following reaction:
$2 NO_{2(g)} \rightarrow 2 NO_{(g)} + O_{2(g)}$
Given that $\left[-\frac{\Delta[NO_2]}{\Delta t}\right] = x \ mol \ dm^{-3} \ s^{-1}$

The differential rate law for the reaction $H_2 + I_2 \to 2HI$ is:

Give the definition of the following terms:
$(i)$ Rate of Reaction
$(ii)$ Average rate of reaction
$(iii)$ Instantaneous rate

Difficult
View Solution

$A \rightarrow P$ is a first order reaction. The following graph is obtained for this reaction,($x$-axis $=$ time; $y$-axis $=$ concentration of $A$). The instantaneous rate of the reaction at point $C$ is

In the reaction $xA \to yB,$
$0.48 + \log \left\{ -\frac{d[A]}{dt} \right\} = \log \left\{ +\frac{d[B]}{dt} \right\} + 0.7$
Then,$x : y$ is

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo