For the reaction,CO_{(g)} + frac{1}{2} O_{2_{ | vedclass

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Question

(A) The relationship between enthalpy change and internal energy change is given by $\Delta H = \Delta U + \Delta n_{g} RT$.For the reaction $CO_{(g)}

Vedclass · Accepted Answer

$\Delta H < \Delta U$

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(A) The relationship between enthalpy change and internal energy change is given by $\Delta H = \Delta U + \Delta n_{g} RT$.For the reaction $CO_{(g)} + \frac{1}{2} O_{2_{(g)}} \longrightarrow CO_{2_{(g)}}$,the change in the number of gaseous moles is $\Delta n_{g} = n_{p(g)} - n_{r(g)} = 1 - (1 + 0.5) = -0.5$.Substituting this into the equation,we get $\Delta H = \Delta U - 0.5 RT$.Since $R$ and $T$ are positive,$-0.5 RT$ is negative,therefore $\Delta H < \Delta U$.

For the reaction,$CO_{(g)} + \frac{1}{2} O_{2_{(g)}} \longrightarrow CO_{2_{(g)}}$,which of the following equations is $CORRECT$ at constant $T$ and $P$?

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