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(C) The given reaction is an intramolecular Cannizzaro reaction because the substrate $4-formylbenzyl alcohol$ contains both an aldehyde group $(-CHO)

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dicarboxylic acid

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(C) The given reaction is an intramolecular Cannizzaro reaction because the substrate $4-formylbenzyl alcohol$ contains both an aldehyde group $(-CHO)$ and a hydroxymethyl group $(-CH_2OH)$,but no $\alpha$-hydrogen atoms.In the presence of concentrated $NaOH$ and heat,the aldehyde group undergoes disproportionation (oxidation and reduction).The oxidation of the $-CHO$ group leads to the formation of a carboxylic acid group $(-COOH)$,while the reduction of the $-CHO$ group leads to the formation of a primary alcohol group $(-CH_2OH)$.The final products are $1,4-benzenedimethanol$ (a diol) and $4-(hydroxymethyl)benzoic acid$ (a compound with both alcohol and acid functional groups).Comparing these products with the options:$A$. Compound with both alcohol and acid functional groups: Formed $(4-(hydroxymethyl)benzoic acid)$.$B$. Monocarboxylic acid: Formed ($4-(hydroxymethyl)benzoic acid$ is a monocarboxylic acid).$C$. Dicarboxylic acid: Not formed.$D$. Diol: Formed ($1,4-benzenedimethanol$ is a diol).Therefore,the compound that is not formed is a dicarboxylic acid.

Column-$I$	Column-$II$
$A$. Acetophenone and Benzophenone	$P$. $NaHCO_3$
$B$. Phenol and Benzoic acid	$Q$. $NaHSO_3$
$C$. Propanone and Ethanal	$R$. $I_2 / NaOH$
$D$. Acetone and Acetophenone	$S$. Fehling solution

For the reaction given below:
The compound which is not formed as a product in the reaction is a:

Similar Questions

Match the Column-$I$ with Column-$II$.

Column-$I$ Column-$II$

$A$. Acetophenone and Benzophenone $P$. $NaHCO_3$

$B$. Phenol and Benzoic acid $Q$. $NaHSO_3$

$C$. Propanone and Ethanal $R$. $I_2 / NaOH$

$D$. Acetone and Acetophenone $S$. Fehling solution

Give the conversion of the following:
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$(ii)$ $Methyl$ $benzoate$ from $benzaldehyde$

The reagent used to distinguish between acetaldehyde and benzaldehyde is

Identify $X$ and $Y$ in the following reaction:

What is the major product formed when salicylaldehyde is reacted with $2$ equivalents of bromine in glacial acetic acid at $0^{\circ} C$?

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For the reaction given below:The compound which is not formed as a product in the reaction is a: