For the reaction given below,which of the fol | vedclass

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(D) The reaction of ethene with aqueous bromine in the presence of $NaCl$ proceeds via the formation of a cyclic bromonium ion intermediate.$1$. The $

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$CH_2(Cl)-CH_2(Cl)$

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(D) The reaction of ethene with aqueous bromine in the presence of $NaCl$ proceeds via the formation of a cyclic bromonium ion intermediate.$1$. The $\pi$-electrons of ethene attack the electrophile $(Br^+)$ to form a cyclic bromonium ion.$2$. This intermediate is then attacked by nucleophiles present in the reaction medium,which include $Br^-$,$Cl^-$,and $H_2O$.$3$. The possible products are:- $Br-CH_2-CH_2-Br$ (from $Br^-$ attack)- $Br-CH_2-CH_2-Cl$ (from $Cl^-$ attack)- $Br-CH_2-CH_2-OH$ (from $H_2O$ attack)$Cl-CH_2-CH_2-Cl$ is not a possible product because the reaction mechanism involves the initial formation of a bromonium ion,meaning at least one bromine atom must be incorporated into the final product. Thus,the correct option is $D$.

For the reaction given below,which of the following is not a possible product?
$H_2C=CH_2 + Br_{2(aq)} \xrightarrow{NaCl} \text{Products}$

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For the reaction given below,which of the following is not a possible product?$H_2C=CH_2 + Br_{2(aq)} \xrightarrow{NaCl} \text{Products}$