For the reaction sequence: P xrightarrow[2. H | vedclass

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(D) The final product is $4	ext{-methylpent-3-en-2-one}$,which is an $\alpha,\beta	ext{-unsaturated ketone}$ formed by the aldol condensation of $2$

Vedclass · Accepted Answer

Ethanenitrile

Vedclass · Answer

(D) The final product is $4	ext{-methylpent-3-en-2-one}$,which is an $\alpha,\beta	ext{-unsaturated ketone}$ formed by the aldol condensation of $2$ molecules of acetone $(CH_3COCH_3)$.Thus,$R$ must be acetone $(CH_3COCH_3)$.The reaction of $P$ with $CH_3MgBr$ followed by hydrolysis yields acetone $(R)$.$CH_3CN + CH_3MgBr$ $ightarrow CH_3C(CH_3)=NMgBr$ $\xrightarrow{H_3O^+} CH_3COCH_3 + NH_3 + Mg(OH)Br$.Therefore,$P$ is $CH_3CN$ (Ethanenitrile).

For the reaction sequence: $P$ $\xrightarrow[2. H_3O^+]{1. CH_3MgBr} R$ $\xrightarrow[2. \Delta]{1. \text{dil. } NaOH} \text{4-methylpent-3-en-2-one}$,identify $P$.

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