For the reaction SnO_{2(s)} + 2H_{2(g)} right | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is $SnO_{2(s)} + 2H_{2(g)} \rightleftharpoons 2H_2O_{(g)} + Sn_{(l)}$.Since $SnO_2$ and $Sn$ are in solid and liquid states respectiv

Vedclass · Accepted Answer

$1.49$

Vedclass · Answer

(A) The reaction is $SnO_{2(s)} + 2H_{2(g)} \rightleftharpoons 2H_2O_{(g)} + Sn_{(l)}$.Since $SnO_2$ and $Sn$ are in solid and liquid states respectively,their activities are taken as $1$.Thus,the equilibrium constant $K_p$ is given by $K_p = \frac{(P_{H_2O})^2}{(P_{H_2})^2}$.Given that the mixture is $45\% \ H_2$ by volume,the mole fraction of $H_2$ is $0.45$ and the mole fraction of $H_2O$ is $1 - 0.45 = 0.55$.Since partial pressure is proportional to mole fraction,$K_p = \left( \frac{0.55}{0.45} \right)^2$.$K_p = (1.222)^2 \approx 1.49$.

List-$I$	List-$II$
$A$. Figure of merit $(k)$	$P$. in series
$B$. Current sensitivity $(S_I)$	$Q$. to get power loss minimized
$C$. Deflection is made half by using resistance	$R$. in shunt/parallel
$D$. High resistance box connected	$S$. current per unit deflection
	$T$. deflection per unit current

For the reaction $SnO_{2(s)} + 2H_{2(g)} \rightleftharpoons 2H_2O_{(g)} + Sn_{(l)}$,calculate $K_p$ at $900 \ K$ where the equilibrium steam-hydrogen mixture was $45\% \ H_2$ by volume.

Similar Questions

Let $O$ be the origin and $A$ be a point on the curve $y^2=4x$. Then the locus of the midpoint of $OA$ is:

Two charges $q_1$ and $q_2$ are placed $30\,cm$ apart,as shown in the figure. $A$ third charge $q_3$ is moved along the arc of a circle of radius $40\,cm$ from $C$ to $D$. The change in the potential energy of the system is $\frac{q_3}{4\pi \epsilon_0}k$,where $k$ is:

Radius of gyration of a body depends on

$\int_{-\pi / 2}^{\pi / 2} \sin ^4 x \cos ^6 x \, dx$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module