For the redox reaction Zn + NO_3^{-} rightarr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The half-reactions are:Oxidation: $Zn \rightarrow Zn^{+2} + 2e^{-}$ (multiplied by $4$ to balance electrons: $4Zn \rightarrow 4Zn^{+2} + 8e^{-}$)R

Vedclass · Accepted Answer

$1, 4, 10$

Vedclass · Answer

(A) The half-reactions are:Oxidation: $Zn \rightarrow Zn^{+2} + 2e^{-}$ (multiplied by $4$ to balance electrons: $4Zn \rightarrow 4Zn^{+2} + 8e^{-}$)Reduction: $NO_3^{-} + 10H^{+} + 8e^{-} \rightarrow NH_4^{+} + 3H_2O$Adding both half-reactions gives the balanced equation:$4Zn + NO_3^{-} + 10H^{+} \rightarrow 4Zn^{+2} + NH_4^{+} + 3H_2O$The coefficients of $NO_3^{-}$,$Zn$,and $H^{+}$ are $1$,$4$,and $10$ respectively.

For the redox reaction $Zn + NO_3^{-} \rightarrow Zn^{+2} + NH_4^{+}$,the coefficients of $NO_3^{-}$,$Zn$,and $H^{+}$ in the balanced equation are respectively:

Similar Questions

In the reaction between hydrogen sulphide and acidified permanganate solution,which of the following occurs?

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$(NH_4)_2Cr_2O_7 \xrightarrow{\Delta} N_2 \uparrow + Cr_2O_3 \downarrow + 4H_2O \uparrow$

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$Cl_{2(g)} + 2KI(aq.) \longrightarrow 2KCl(aq.) + I_2(s)$

Explain why the colour of $KMnO_4$ disappears when oxalic acid is added to its solution in acidic medium.

The number of moles of $K_2Cr_2O_7$ reduced by $1 \ mol$ of $Sn^{+2}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module