For the spontaneity of a reaction,which state | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The spontaneity of a reaction is determined by the Gibbs free energy equation: $\Delta G = \Delta H - T\Delta S$. For a reaction to be spontaneous

Vedclass · Accepted Answer

$\Delta H = - ve$; $\Delta S = + ve$

Vedclass · Answer

(D) The spontaneity of a reaction is determined by the Gibbs free energy equation: $\Delta G = \Delta H - T\Delta S$. For a reaction to be spontaneous,$\Delta G$ must be negative $(\Delta G If $\Delta H$ is negative (exothermic) and $\Delta S$ is positive (increase in entropy),then $\Delta G = (	ext{negative}) - T(	ext{positive})$. Since $T$ (absolute temperature) is always positive,$-T\Delta S$ will be negative. Therefore,$\Delta G$ will always be negative regardless of the temperature,making the reaction always spontaneous.

For the spontaneity of a reaction,which statement is always true?

Similar Questions

For the melting of $3 \ mol$ of ice at $0^o \text{C}$,$\Delta G = \dots \dots$

Gibbs free energy $G$,enthalpy $H$ and entropy $S$ are interrelated as in

At $273 \ K$ the maximum work done when pressure on $10 \ g$ of hydrogen is reduced from $10 \ atm$ to $1 \ atm$ under isothermal,reversible conditions is (Assume the gas behaves ideally) $(R=8.3 \ J \ K^{-1} \ mol^{-1})$

The free energy for a reaction having $\Delta H = 31400 \, cal$ and $\Delta S = 32 \, cal \, K^{-1} \, mol^{-1}$ at $1000 \, ^oC$ is ....... $cal$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module