For the transformation shown below,the reagen | vedclass

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(B) The given reaction involves the removal of the diazonium group $(-N_2^{+}Cl^{-})$ from the benzene ring and its replacement with a hydrogen atom.T

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$H_3PO_2$

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(B) The given reaction involves the removal of the diazonium group $(-N_2^{+}Cl^{-})$ from the benzene ring and its replacement with a hydrogen atom.This is a reductive deamination reaction of a diazonium salt.$H_3PO_2$ (hypophosphorous acid) in the presence of water is a standard reagent used to reduce diazonium salts to the corresponding arenes.The reaction is:$Ar-N_2^{+}Cl^{-} + H_3PO_2 + H_2O \rightarrow Ar-H + N_2 + H_3PO_3 + HCl$Therefore,the correct reagent is $H_3PO_2$.

For the transformation shown below,the reagent used is:
$3-bromobenzenediazonium \ chloride \rightarrow \text{bromobenzene}$

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For the transformation shown below,the reagent used is:$3-bromobenzenediazonium \ chloride \rightarrow \text{bromobenzene}$