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(D) The electric field due to an infinitely long charged sheet with surface charge density $\sigma$ is given by $E = \frac{\sigma}{2\varepsilon_0}$.Le

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(D) The electric field due to an infinitely long charged sheet with surface charge density $\sigma$ is given by $E = \frac{\sigma}{2\varepsilon_0}$.Let the left sheet be at position $0$ and the right sheet be at position $r$. Both sheets have a positive surface charge density $\sigma$.At a point $P$ located at a distance $x$ from the left sheet,the electric field due to the left sheet $(E_1)$ points to the right and is given by $E_1 = \frac{\sigma}{2\varepsilon_0}$.The electric field due to the right sheet $(E_2)$ at point $P$ points to the left and is given by $E_2 = \frac{\sigma}{2\varepsilon_0}$.The net electric field $E_{net}$ at point $P$ is the vector sum of these two fields:$E_{net} = E_1 - E_2 = \frac{\sigma}{2\varepsilon_0} - \frac{\sigma}{2\varepsilon_0} = 0$.Therefore,the electric field at point $P$ is $0$.

For two infinitely long charged parallel sheets with the same surface charge density $\sigma$,the electric field at point $P$ between them is:

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