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(D) The rate of ice formation is given by the relation $t \propto (x_2^2 - x_1^2)$,where $x$ is the thickness of the ice layer.For the first $3 \ mm$

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(D) The rate of ice formation is given by the relation $t \propto (x_2^2 - x_1^2)$,where $x$ is the thickness of the ice layer.For the first $3 \ mm$ $(x_1 = 3 \ mm)$,the time taken is $t_1 = 1 \ hour$.For the next $6 \ mm$,the total thickness becomes $x_2 = 3 \ mm + 6 \ mm = 9 \ mm$.The time taken for the total thickness of $9 \ mm$ is $T$.The time taken for the next $6 \ mm$ is $t_2 = T - t_1$.Using the proportionality: $\frac{t_1}{T} = \frac{x_1^2}{x_2^2} = \frac{3^2}{9^2} = \frac{9}{81} = \frac{1}{9}$.So,$T = 9 	imes t_1 = 9 	imes 1 = 9 \ hours$.The time taken for the next $6 \ mm$ is $t_2 = 9 - 1 = 8 \ hours$.

For water at $0^{\circ} C$,it takes one hour for the first $3 \ mm$ of ice layer formation. How many hours will it take for the next $6 \ mm$ of ice formation?

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