For which of the following,the radius will be | vedclass

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(C) The radius of an orbit in a hydrogen-like species is given by the formula $r_n = a_0 	imes \frac{n^2}{Z}$,where $a_0$ is the Bohr radius,$n$ is t

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$Be^{3+}, n = 2$

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(C) The radius of an orbit in a hydrogen-like species is given by the formula $r_n = a_0 	imes \frac{n^2}{Z}$,where $a_0$ is the Bohr radius,$n$ is the principal quantum number,and $Z$ is the atomic number. For a hydrogen atom with $n = 1$ and $Z = 1$,the radius is $r_H = a_0 	imes \frac{1^2}{1} = a_0$. Now,checking the options: For $Be^{3+}$,$n = 2$ and $Z = 4$,so $r = a_0 	imes \frac{2^2}{4} = a_0 	imes \frac{4}{4} = a_0$. Thus,the radius of $Be^{3+}$ with $n = 2$ is equal to the radius of a hydrogen atom with $n = 1$.

For which of the following,the radius will be the same as that of a hydrogen atom having $n = 1$?

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