For which of the following pairs of complexes | vedclass

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(C) The crystal field splitting energy $\Delta_0$ depends on the oxidation state of the metal ion,the nature of the ligand,and the principal quantum n

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$a, b, c, d$

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(C) The crystal field splitting energy $\Delta_0$ depends on the oxidation state of the metal ion,the nature of the ligand,and the principal quantum number of the metal ($3d$ vs $4d$ vs $5d$).$(a)$ $[Cr(H_2O)_6]^{2+}$ vs $[Cr(H_2O)_6]^{3+}$: Higher oxidation state $(+3 > +2)$ leads to larger $\Delta_0$. Thus,$II > I$.$(b)$ $[Fe(H_2O)_6]^{3+}$ vs $[Fe(CN)_6]^{3-}$: $CN^-$ is a stronger field ligand than $H_2O$,leading to larger $\Delta_0$. Thus,$II > I$.$(c)$ $[Fe(CN)_6]^{3-}$ vs $[Ru(CN)_6]^{3-}$: $Ru$ is a $4d$ metal while $Fe$ is a $3d$ metal. $\Delta_0$ increases down the group. Thus,$II > I$.$(d)$ $[NiF_6]^{4-}$ vs $[NiF_6]^{2-}$: Higher oxidation state $(+4 > +2)$ leads to larger $\Delta_0$. Thus,$II > I$.All pairs satisfy the condition $\Delta_0(II) > \Delta_0(I)$.

$I$	$II$
$(a). [Cr(H_2O)_6]^{2+}$	$[Cr(H_2O)_6]^{3+}$
$(b). [Fe(H_2O)_6]^{3+}$	$[Fe(CN)_6]^{3-}$
$(c). [Fe(CN)_6]^{3-}$	$[Ru(CN)_6]^{3-}$
$(d). [NiF_6]^{4-}$	$[NiF_6]^{2-}$

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For which of the following pairs of complexes is the crystal field splitting energy $\Delta_0$ for $II > \Delta_0$ for $I$? $I$ $II$ $(a). [Cr(H_2O)_6]^{2+}$ $[Cr(H_2O)_6]^{3+}$ $(b). [Fe(H_2O)_6]^{3+}$ $[Fe(CN)_6]^{3-}$ $(c). [Fe(CN)_6]^{3-}$ $[Ru(CN)_6]^{3-}$ $(d). [NiF_6]^{4-}$ $[NiF_6]^{2-}$