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(C) The magnitude of crystal field splitting energy $(\Delta_0)$ depends on the strength of the ligand according to the spectrochemical series.Stronge

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$[Co(H_2O)_6]^{3+}$

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(C) The magnitude of crystal field splitting energy $(\Delta_0)$ depends on the strength of the ligand according to the spectrochemical series.Stronger ligands cause larger splitting,while weaker ligands cause smaller splitting.The spectrochemical series for the given ligands is: $CN^- > NH_3 > C_2O_4^{2-} > H_2O$.However,comparing the specific complexes provided,$H_2O$ is a weak field ligand compared to $CN^-$,$NH_3$,and $C_2O_4^{2-}$.Among the given options,$[Co(H_2O)_6]^{3+}$ contains the weakest ligand,resulting in the lowest value of $\Delta_0$.

List-$I$ (Electronic configuration of tetrahedral metal ion)	List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)
$A$. $d^2$	$I$. $-0.6$
$B$. $d^4$	$II$. $-0.8$
$C$. $d^6$	$III$. $-1.2$
$D$. $d^8$	$IV$. $-0.4$

For which of the following complexes will the value of $\Delta_0$ be the lowest?

Similar Questions

The number of unpaired $d$-electrons in $[Co(H_2O)_6]^{3+}$ is $\qquad$

The correct order for wavelengths of absorption in the visible region for the following complexes will be

Match the $LIST$-$I$ with $LIST$-$II$:

List-$I$ (Electronic configuration of tetrahedral metal ion) List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)

$A$. $d^2$ $I$. $-0.6$

$B$. $d^4$ $II$. $-0.8$

$C$. $d^6$ $III$. $-1.2$

$D$. $d^8$ $IV$. $-0.4$

Explain crystal field splitting in octahedral complexes.

The crystal field theory is successful in explaining which of the following?
$I.$ Ligands as point charges;
$II.$ Formation and structures of complexes.
$III.$ Colour;
$IV.$ Magnetic properties;
$V.$ Covalent character of metal-ligand bonding.

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