For which reaction is Delta H neq Delta U? | vedclass

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(C) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta U)$ is given by the equation: $\Delta H = \Delta U + \De

Vedclass · Accepted Answer

$N_{2(g)} + 3 H_{2(g)} \longrightarrow 2 NH_{3(g)}$

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(C) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta U)$ is given by the equation: $\Delta H = \Delta U + \Delta n_g RT$,where $\Delta n_g$ is the change in the number of moles of gaseous products and reactants.For $\Delta H 
eq \Delta U$,we must have $\Delta n_g 
eq 0$.$(A)$ $\Delta n_g = 2 - (1 + 1) = 0$.$(B)$ $\Delta n_g = (1 + 1) - 2 = 0$.$(C)$ $\Delta n_g = 2 - (1 + 3) = 2 - 4 = -2$. Since $\Delta n_g 
eq 0$,$\Delta H 
eq \Delta U$.$(D)$ $\Delta n_g = 1 - (0 + 1) = 0$ (Note: $C_{(s)}$ is a solid,so its moles are not counted in $\Delta n_g$).Therefore,the correct option is $C$.

For which reaction is $\Delta H \neq \Delta U$?

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