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Question

(C) The force $F$ between two magnetic poles of strengths $m_1$ and $m_2$ separated by a distance $r$ is given by Coulomb's law for magnetism:$F = \fr

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$10^{-7} \, N$

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(C) The force $F$ between two magnetic poles of strengths $m_1$ and $m_2$ separated by a distance $r$ is given by Coulomb's law for magnetism:$F = \frac{\mu_0}{4\pi} \cdot \frac{m_1 m_2}{r^2}$Given that the pole strengths are unit pole strengths,$m_1 = 1 \, Am$ and $m_2 = 1 \, Am$.The distance $r = 1 \, m$.The value of $\frac{\mu_0}{4\pi} = 10^{-7} \, N/A^2$.Substituting these values into the formula:$F = 10^{-7} 	imes \frac{1 	imes 1}{1^2} = 10^{-7} \, N$.

The force between two unit pole strengths placed at a distance of $1 \, m$ is:

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