Formaldehyde reacts with methyl magnesium iod | vedclass

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Question

(B) The reaction of formaldehyde $(HCHO)$ with methyl magnesium iodide $(CH_3MgI)$ is a nucleophilic addition reaction.Step $1$: Formaldehyde reacts w

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Ethyl alcohol

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(B) The reaction of formaldehyde $(HCHO)$ with methyl magnesium iodide $(CH_3MgI)$ is a nucleophilic addition reaction.Step $1$: Formaldehyde reacts with $CH_3MgI$ to form an addition product: $HCHO + CH_3MgI \rightarrow CH_3CH_2OMgI$.Step $2$: Aqueous hydrolysis of the addition product yields ethyl alcohol: $CH_3CH_2OMgI + H_2O \rightarrow CH_3CH_2OH + Mg(OH)I$.Thus,the final product is ethyl alcohol $(CH_3CH_2OH)$.

Formaldehyde reacts with methyl magnesium iodide to form an additive product,which upon aqueous hydrolysis yields:

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