(B) Let the capacitance of each capacitor be $C$.When $4$ capacitors are connected in series, the equivalent capacitance $C_1$ is given by $\frac{1}{C

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(B) Let the capacitance of each capacitor be $C$.When $4$ capacitors are connected in series, the equivalent capacitance $C_1$ is given by $\frac{1}{C_1} = \frac{1}{C} + \frac{1}{C} + \frac{1}{C} + \frac{1}{C} = \frac{4}{C}$, which implies $C_1 = \frac{C}{4}$.When $4$ capacitors are connected in parallel, the equivalent capacitance $C_2$ is given by $C_2 = C + C + C + C = 4C$.Now, the ratio $\frac{C_1}{C_2}$ is calculated as $\frac{C/4}{4C} = \frac{1}{16}$.

Class 12 Physics Electrostatic Potential and Capacitance Equivalent Capacitance of Capacitor connected in Series and Parallel

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Four capacitors of equal capacitance have an equivalent capacitance $C_1$ when connected in series and an equivalent capacitance $C_2$ when connected in parallel. The ratio $\frac{C_1}{C_2}$ is:

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A
$1 / 4$
B
$1 / 16$
C
$1 / 8$
D
$1 / 12$

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Electrostatic Potential and Capacitance

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Equivalent Capacitance of Capacitor connected in Series and Parallel

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Four capacitors of equal capacitance have an equivalent capacitance $C_1$ when connected in series and an equivalent capacitance $C_2$ when connected in parallel. The ratio $\frac{C_1}{C_2}$ is:

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