Four identical bulbs,each rated 100 , W, 220 | vedclass

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(A) The resistance $R$ of each bulb is given by $R = \frac{V^2}{P} = \frac{220^2}{100} \, \Omega$.In the circuit,one bulb is in series with a parallel

Vedclass · Accepted Answer

$75$

Vedclass · Answer

(A) The resistance $R$ of each bulb is given by $R = \frac{V^2}{P} = \frac{220^2}{100} \, \Omega$.In the circuit,one bulb is in series with a parallel combination of three bulbs.The equivalent resistance of the three bulbs in parallel is $R_p = \frac{R}{3}$.The total equivalent resistance of the circuit is $R_{eq} = R + R_p = R + \frac{R}{3} = \frac{4R}{3}$.Substituting the value of $R$:$R_{eq} = \frac{4}{3} 	imes \frac{220^2}{100} = \frac{4 	imes 220^2}{300}$.The total power consumed by the circuit is $P_{total} = \frac{V^2}{R_{eq}} = \frac{220^2}{\frac{4 	imes 220^2}{300}} = \frac{300}{4} = 75 \, W$.

Four identical bulbs,each rated $100 \, W, 220 \, V$,are connected across a battery as shown. The total electric power consumed by the bulbs is.......$W$.

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