Four successive members of the first series o | vedclass

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Question

(C) The standard electrode potential $(E^o_{M^{2+}/M})$ depends on the sum of the enthalpy of atomization,ionization enthalpy,and hydration enthalpy.

Vedclass · Accepted Answer

$Cu (Z = 29)$

Vedclass · Answer

(C) The standard electrode potential $(E^o_{M^{2+}/M})$ depends on the sum of the enthalpy of atomization,ionization enthalpy,and hydration enthalpy. For most transition metals,the value of $(E^o_{M^{2+}/M})$ is negative. However,for $Cu$,the high energy to transform $Cu(s)$ to $Cu^{2+}(aq)$ is not compensated by its hydration enthalpy,resulting in a positive $(E^o_{M^{2+}/M})$ value of $+0.34 \ V$. Therefore,$Cu$ is the correct answer.

Four successive members of the first series of the transition metals are listed below. For which one of them is the standard electrode potential $(E^o_{M^{2+}/M})$ value positive?

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