Frequency of heterozygous gene in Hardy-Weinb | vedclass

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(C) In the Hardy-Weinberg principle,the equation is given by $(p + q)^2 = p^2 + 2pq + q^2 = 1$.Here,$p$ represents the frequency of the dominant allel

Vedclass · Accepted Answer

$2pq$

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(C) In the Hardy-Weinberg principle,the equation is given by $(p + q)^2 = p^2 + 2pq + q^2 = 1$.Here,$p$ represents the frequency of the dominant allele and $q$ represents the frequency of the recessive allele.$p^2$ represents the frequency of homozygous dominant individuals.$q^2$ represents the frequency of homozygous recessive individuals.$2pq$ represents the frequency of heterozygous individuals.Therefore,the frequency of the heterozygous gene is represented by $2pq$.

Frequency of heterozygous gene in Hardy-Weinberg principle is represented by . . . . . . .

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