From a book containing 100 pages,one page is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total number of pages is $100$,so the sample space is $\{1, 2, 3, \dots, 100\}$.We need to find the page numbers whose digits sum to $11$.For

Vedclass · Accepted Answer

$\frac{2}{25}$

Vedclass · Answer

(A) The total number of pages is $100$,so the sample space is $\{1, 2, 3, \dots, 100\}$.We need to find the page numbers whose digits sum to $11$.For a two-digit number $xy$,the sum is $x + y = 11$. The possible pairs $(x, y)$ are $(2, 9), (3, 8), (4, 7), (5, 6), (6, 5), (7, 4), (8, 3), (9, 2)$.These correspond to the page numbers: $29, 38, 47, 56, 65, 74, 83, 92$.There are $8$ such pages.Note that for the page number $100$,the sum of digits is $1 + 0 + 0 = 1 
eq 11$.Thus,the number of favourable outcomes is $8$.The probability is $\frac{8}{100} = \frac{2}{25}$.

From a book containing $100$ pages,one page is selected randomly. The probability that the sum of the digits of the page number of the selected page is $11$,is

Similar Questions

If $A, B, C$ are three mutually exclusive and exhaustive events of an experiment such that $P(A)=2 P(B)=3 P(C)$,then $P(B)$ is equal to

$X$ speaks truth in $60\%$ and $Y$ in $50\%$ of the cases. The probability that they contradict each other in narrating the same incident is

One card is drawn from a well-shuffled deck of $52$ cards. If each outcome is equally likely,calculate the probability that the card will be a diamond but not an ace.

The probability of happening an event $A$ is $0.5$ and that of $B$ is $0.3$. If $A$ and $B$ are mutually exclusive events,then the probability of happening neither $A$ nor $B$ is

$A, B$ and $C$ are mutually exclusive events. If $P(A) = \frac{3x + 1}{3}$,$P(B) = \frac{1 - x}{4}$,and $P(C) = \frac{1 - 2x}{2}$,then the possible values of $x$ lie in the interval ...

Vedclass Test Series

Exam Paper Generator

Online Exam Module