From a cross AABb times aaBb,the genotypes Aa | vedclass

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(B) The cross is $AABb 	imes aaBb$.We can solve this by considering the inheritance of each gene pair independently:$1$. For the $A$ gene: $AA 	imes

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$1 : 2 : 1 : 0$

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(B) The cross is $AABb 	imes aaBb$.We can solve this by considering the inheritance of each gene pair independently:$1$. For the $A$ gene: $AA 	imes aa$ results in $100\% Aa$.$2$. For the $B$ gene: $Bb 	imes Bb$ results in $1 BB : 2 Bb : 1 bb$.Combining these results:- $AaBB = 1 	imes 1 = 1$- $AaBb = 1 	imes 2 = 2$- $Aabb = 1 	imes 1 = 1$- $aabb = 1 	imes 0 = 0$Thus,the ratio of $AaBB : AaBb : Aabb : aabb$ is $1 : 2 : 1 : 0$.

From a cross $AABb \times aaBb$,the genotypes $AaBB : AaBb : Aabb : aabb$ will be obtained in the following ratio:

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