From a fixed support,two small identical sphe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The time period of a simple pendulum is given by $T = 2 \pi \sqrt{\frac{l}{g}}$.Given $l = 1 \,m$ and taking $g = 10 \,m/s^2$ (or $\pi^2 \approx 1

Vedclass · Accepted Answer

at $B$ after $0.5 \,s$

Vedclass · Answer

(B) The time period of a simple pendulum is given by $T = 2 \pi \sqrt{\frac{l}{g}}$.Given $l = 1 \,m$ and taking $g = 10 \,m/s^2$ (or $\pi^2 \approx 10$),we have $T = 2 \pi \sqrt{\frac{1}{10}} \approx 2 \,s$.For a simple pendulum,the time taken to travel from the extreme position to the mean position $(B)$ is $\frac{T}{4}$.Since both spheres are released from their respective extreme positions,they will both reach the mean position $B$ at time $t = \frac{T}{4} = \frac{2}{4} = 0.5 \,s$.Therefore,the two spheres will collide at the mean position $B$ after $0.5 \,s$.

From a fixed support,two small identical spheres are suspended by means of strings of length $1 \,m$ each. They are pulled aside as shown and then released. $B$ is the mean position. Then the two spheres collide

Similar Questions

$A$ simple pendulum of length $l$ has a brass bob attached at its lower end. Its period is $T$. $A$ steel bob of the same size,having density $x$ times that of brass,replaces the brass bob. Its length is then changed such that the period becomes $2T$. What is the new length?

$A$ simple pendulum of length $2 \ m$ is given a horizontal push through an angular displacement of $60^{\circ}$. If the mass of the bob is $200 \ g$,the angular velocity of the bob will be (Take acceleration due to gravity $g = 10 \ m/s^2$).

$A$ pendulum clock is running slow. In order to correct it, we should:

If the length of an oscillating simple pendulum is made $\frac{1}{3}$ times at a place while keeping the amplitude the same,then its total energy $(E)$ will be: (in $E$)

$A$ pendulum is executing simple harmonic motion and its maximum kinetic energy is $K_1$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same angular amplitude as in the first case,its maximum kinetic energy is $K_2$,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module