From a pack of cards,two are drawn,the first | vedclass

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(C) Let $A$ be the event that the first card is a diamond.Let $B$ be the event that the second card is a king.Since the first card is replaced before

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$\frac{1}{52}$

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(C) Let $A$ be the event that the first card is a diamond.Let $B$ be the event that the second card is a king.Since the first card is replaced before the second is drawn,the events $A$ and $B$ are independent.The probability of drawing a diamond is $P(A) = \frac{13}{52} = \frac{1}{4}$.The probability of drawing a king is $P(B) = \frac{4}{52} = \frac{1}{13}$.Since the events are independent,the required probability is $P(A \cap B) = P(A) 	imes P(B)$.Therefore,the required probability $= \frac{1}{4} 	imes \frac{1}{13} = \frac{1}{52}$.

From a pack of cards,two are drawn,the first being replaced before the second is drawn. Find the probability that the first is a diamond and the second is a king.

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