From out of $100$ enrolled students,two sections of strength $40$ and $60$ are formed. If you and your friend are among those $100$ students,then the probability that both of you are placed in the same section is
- A$\frac{{ }^{98} C_{40}+{ }^{98} C_{58}}{{ }^{100} C_{40}}$
- B$\frac{{ }^{40} C_2+{ }^{60} C_2}{{ }^{100} C_2}$
- C$\frac{{ }^{98} C_{60}+{ }^{98} C_{38}}{{ }^{100} C_{60}}$
- D$\frac{{ }^{98} C_{58}+{ }^{98} C_0}{{ }^{100} C_2}$
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