From the following sets of quantum numbers, w | vedclass

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(C) The rules for quantum numbers are: $1$. $n = 1, 2, 3, \dots$ $2$. $l = 0$ to $(n-1)$ $3$. $m_l = -l$ to $+l$ $4$. $m_s = \pm \frac{1}{2}$ Check ea

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$n=3, l=1, m_l=0, m_s=+\frac{1}{2}$

Vedclass · Answer

(C) The rules for quantum numbers are: $1$. $n = 1, 2, 3, \dots$ $2$. $l = 0$ to $(n-1)$ $3$. $m_l = -l$ to $+l$ $4$. $m_s = \pm \frac{1}{2}$ Check each option: $(A)$ For $n=1, l=0$, the only possible value for $m_l$ is $0$. Thus, $m_l=+1$ is incorrect. $(B)$ For $n=1$, $l$ can only be $0$. Thus, $l=1$ is incorrect. $(C)$ For $n=3$, $l$ can be $0, 1, 2$. If $l=1$, $m_l$ can be $-1, 0, +1$. Since $m_l=0$ and $m_s=+\frac{1}{2}$ are valid, this set is possible. $(D)$ For $n=3$, $l$ can only be $0, 1, 2$. Thus, $l=3$ is incorrect. Therefore, option $(C)$ is correct.

From the following sets of quantum numbers, which set is possible?

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