From the top of a tower,two stones,whose mass | vedclass

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Question

(C) Let the height of the tower be $h$. The acceleration due to gravity is $g$ acting downwards.For the first stone thrown upwards with speed $u$:When

Vedclass · Accepted Answer

Both the stones will have the same speed when they hit the ground.

Vedclass · Answer

(C) Let the height of the tower be $h$. The acceleration due to gravity is $g$ acting downwards.For the first stone thrown upwards with speed $u$:When it returns to the level of the tower top,its speed is $u$ downwards. Using the third equation of motion $v^2 = u^2 + 2as$,where $v$ is the final speed at the ground,$u$ is the initial speed at the tower top,$a = g$,and $s = h$:$v_1^2 = u^2 + 2gh$For the second stone thrown downwards with speed $u$:Using the same equation of motion with initial speed $u$ downwards and $a = g$:$v_2^2 = u^2 + 2gh$Since the final speeds $v_1$ and $v_2$ depend only on the initial speed $u$,the height $h$,and the acceleration $g$,both stones will hit the ground with the same speed. The mass does not affect the final speed in the absence of air resistance.Therefore,option $C$ is correct.

From the top of a tower,two stones,whose masses are in the ratio $1:2$,are thrown: one straight up with an initial speed $u$ and the second straight down with the same speed $u$. Neglecting air resistance,which of the following is true?

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