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(B) The graph shows a straight line with a positive slope,which means the acceleration $a = \frac{dv}{dt}$ is constant. Since $F = ma$,a constant acce

Vedclass · Accepted Answer

The speed of the particle increases continuously.

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(B) The graph shows a straight line with a positive slope,which means the acceleration $a = \frac{dv}{dt}$ is constant. Since $F = ma$,a constant acceleration implies a constant force.As the particle moves,its velocity changes from negative to positive. The area under the $v-t$ graph represents displacement. Since the graph crosses the time axis,the net displacement can become zero,meaning the particle crosses its initial position.However,the speed is the magnitude of velocity $|v|$. As the particle moves from a negative velocity towards zero and then to positive values,its speed first decreases (as it approaches zero) and then increases. Therefore,the statement that the speed increases continuously is incorrect.

From the velocity-time graph of a particle moving in a straight line,decide which of the following is an incorrect statement.

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