From two points,lying on the same horizontal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $AC$ be the height of the pillar $= h \ m$.Let $B$ and $D$ be the two points on the same horizontal line such that $\angle ABC = 	heta$ and $

Vedclass · Accepted Answer

$h(\cot 	heta - \cot \phi)$

Vedclass · Answer

(C) Let $AC$ be the height of the pillar $= h \ m$.Let $B$ and $D$ be the two points on the same horizontal line such that $\angle ABC = 	heta$ and $\angle ADC = \phi$.In $	riangle ADC$,$	an \phi = \frac{AC}{CD} = \frac{h}{CD}$,so $CD = h \cot \phi$.In $	riangle ABC$,$	an 	heta = \frac{AC}{CB} = \frac{h}{CB}$,so $CB = h \cot 	heta$.The distance between the two points $B$ and $D$ is $BD = CB - CD$.Substituting the values,$BD = h \cot 	heta - h \cot \phi = h(\cot 	heta - \cot \phi)$.

From two points,lying on the same horizontal line,the angles of elevation of the top of the pillar are $\theta$ and $\phi$ $(\theta < \phi)$. If the height of the pillar is $h$ $m$ and the two points lie on the same side of the pillar,then the distance between the two points is (in $m$):

Similar Questions

If $\frac{\sin A - \sin C}{\cos C - \cos A} = \cot B,$ then $A, B, C$ are in

If $\cos \theta + \sin \theta = \sqrt{2} \cos \theta$,then $\cos \theta - \sin \theta =$

If $a \cos 2\theta + b \sin 2\theta = c$ has $\alpha$ and $\beta$ as its solutions,then the value of $\tan \alpha + \tan \beta$ is

If $\cos A = \frac{3}{4}$,then $32\sin \frac{A}{2}\cos \frac{5A}{2} = $

The value of $\cos^{3}\left(\frac{\pi}{8}\right) \cdot \cos\left(\frac{3\pi}{8}\right) + \sin^{3}\left(\frac{\pi}{8}\right) \cdot \sin\left(\frac{3\pi}{8}\right)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module