Give the meaning of $10\%$ glucose by weight.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The expression $10\%$ glucose by weight means that $10 \ g$ of glucose is dissolved in $90 \ g$ of water,resulting in a total mass of $100 \ g$ of the solution.
Mathematically,it is defined as:
$\text{Mass percentage} = \frac{\text{Mass of solute}}{\text{Mass of solution}} \times 100$
$\frac{10 \ g \text{ glucose}}{100 \ g \text{ solution}} \times 100 = 10\%$.

Explore More

Similar Questions

$125 \, cm^3$ of isopropyl alcohol is added to water to make a solution of volume $175 \, cm^3$. Find the volume fraction and volume percentage of isopropyl alcohol in the solution.

Which of the following statements is true?
$(1)$ $200 \ mL$ of $0.2 \ M \ NaOH$ has the same number of moles of solute as $1000 \ mL$ of $1 \ M \ NaOH$.
$(2)$ $200 \ mL$ of $1 \ M \ NaOH$ has the same number of moles as $1000 \ mL$ of $0.2 \ M \ NaOH$.
$(3)$ $100 \ mL$ of $0.2 \ M \ NaOH$ has the same number of moles as $1000 \ mL$ of $1 \ M \ NaOH$.
$(4)$ $2000 \ mL$ of $0.2 \ M \ NaOH$ has the same number of moles as $1000 \ mL$ of $1 \ M \ NaOH$.

Calculate the concentration of sugar $(C_{12}H_{22}O_{11})$ in $mol \ L^{-1}$ if $20 \ g$ of sugar is dissolved in sufficient water to make the final volume $2 \ L$.

Difficult
View Solution

What is the molarity of the solution formed by adding $3 \, L$ of $0.5 \, M$ $NaOH$ solution to $2.5 \, L$ of $1 \, M$ $NaOH$ solution?

If $80 \ g$ of $NaOH$ is mixed with $54 \ g$ of water to form a solution,calculate the mole fraction of water.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo