Class 11Physics1 Thermal Properties of Matter: Thermometry, Expansion and CalorimetryMix Examples-Thermometry, Thermal Expansion and Calorimetry
MediumGive one example each for solid,liquid,and gas showing expansion with an increase in temperature and contraction with a decrease in temperature.
(N/A) For Solids: $A$ metallic lid on a glass jar that is stuck can be opened by placing it in hot water. The heat causes the metallic lid to expand more than the glass,loosening it for easy removal.
For Liquids: The mercury in a clinical thermometer rises when placed in warm water due to thermal expansion. When the thermometer is removed and cooled,the mercury level falls due to contraction.
For Gases: $A$ partially inflated balloon placed in warm water will expand as the air inside gains kinetic energy and occupies more volume. Conversely,a fully inflated balloon placed in cold water will shrink as the air inside contracts.
For Liquids: The mercury in a clinical thermometer rises when placed in warm water due to thermal expansion. When the thermometer is removed and cooled,the mercury level falls due to contraction.
For Gases: $A$ partially inflated balloon placed in warm water will expand as the air inside gains kinetic energy and occupies more volume. Conversely,a fully inflated balloon placed in cold water will shrink as the air inside contracts.
Explore More
Similar Questions
The amount of heat needed to heat $200 \ g$ of ice at $-10^{\circ}C$ to convert it into water at $30^{\circ}C$ is:
Specific heat capacity of ice $= 2100 \ J \ kg^{-1} \ K^{-1}$
Specific heat capacity of water $= 4186 \ J \ kg^{-1} \ K^{-1}$
Latent heat of fusion of ice $= 3.35 \times 10^5 \ J \ kg^{-1}$ (in $J$)
Specific heat capacity of ice $= 2100 \ J \ kg^{-1} \ K^{-1}$
Specific heat capacity of water $= 4186 \ J \ kg^{-1} \ K^{-1}$
Latent heat of fusion of ice $= 3.35 \times 10^5 \ J \ kg^{-1}$ (in $J$)
How much thermal energy is required to change a $40 \ g$ ice cube from solid at $-10^{\circ} C$ to steam at $110^{\circ} C$ (in $kcal$)?
[Assume, latent heat of fusion for water $= 80 \ kcal/kg$, specific heat of water $= 1 \ kcal/kg^{\circ} C$, specific heat of ice $= 0.5 \ kcal/kg^{\circ} C$, specific heat of steam $= 0.48 \ kcal/kg^{\circ} C$, latent heat of vaporisation of water $= 540 \ kcal/kg$]
[Assume, latent heat of fusion for water $= 80 \ kcal/kg$, specific heat of water $= 1 \ kcal/kg^{\circ} C$, specific heat of ice $= 0.5 \ kcal/kg^{\circ} C$, specific heat of steam $= 0.48 \ kcal/kg^{\circ} C$, latent heat of vaporisation of water $= 540 \ kcal/kg$]
By exerting a certain amount of pressure on an ice block,you:
Easy
View SolutionThe height of a waterfall is $50 \ m$. If $g = 9.8 \ m/s^2$, the difference between the temperature at the top and the bottom of the waterfall is: (in $^{\circ} C$)
DifficultWBJEE 2009
View SolutionCalculate the amount of heat (in calories) required to convert $5\,g$ of ice at $0^{\circ}C$ to steam at $100^{\circ}C$.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo