Given lambda^{circ}_{Mg^{2+}} = 106 S cm^2 | vedclass

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(B) This question is based on Kohlrausch's law of independent migration of ions.According to this law,at infinite dilution,the molar conductivity of a

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$266$

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(B) This question is based on Kohlrausch's law of independent migration of ions.According to this law,at infinite dilution,the molar conductivity of an electrolyte is the sum of the molar conductivities of its constituent ions.$\lambda^{\circ}_{MgSO_4} = \lambda^{\circ}_{Mg^{2+}} + \lambda^{\circ}_{SO_4^{2-}}$Substituting the given values:$\lambda^{\circ}_{MgSO_4} = 106 \ S \ cm^2 \ mole^{-1} + 160 \ S \ cm^2 \ mole^{-1} = 266 \ S \ cm^2 \ mole^{-1}$

Given $\lambda^{\circ}_{Mg^{2+}} = 106 \ S \ cm^2 \ mole^{-1}$ and $\lambda^{\circ}_{SO_4^{2-}} = 160 \ S \ cm^2 \ mole^{-1}$. The value of $\lambda^{\circ}_{MgSO_4}$ (in $S \ cm^2 \ mole^{-1}$) is

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