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(C) According to $Dobereiner's$ law of triads,the atomic mass of the middle element is approximately the arithmetic mean of the atomic masses of the o

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$Cl, K, Ca$

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(C) According to $Dobereiner's$ law of triads,the atomic mass of the middle element is approximately the arithmetic mean of the atomic masses of the other two elements.$1$. For $Li, Na, K$: $\frac{7 + 39}{2} = 23$ (Forms a triad).$2$. For $Ca, Sr, Ba$: $\frac{40 + 137}{2} = 88.5 \approx 88$ (Forms a triad).$3$. For $Cl, Br, I$: $\frac{35.5 + 127}{2} = 81.25 \approx 80$ (Forms a triad).$4$. For $Cl, K, Ca$: The atomic masses are $35.5, 39,$ and $40$. The average of $35.5$ and $40$ is $37.75$,which is not equal to $39$. Thus,it does not form a triad.

Given below are the atomic masses of the elements:

Element $Li$ $Na$ $Cl$ $K$ $Ca$ $Br$ $Sr$ $I$ $Ba$

Atomic Mass $(g \cdot mol^{-1})$ $7$ $23$ $35.5$ $39$ $40$ $80$ $88$ $127$ $137$

Which of the following does not form a $Dobereiner's$ triad?

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Given below are the atomic masses of the elements: Element $Li$ $Na$ $Cl$ $K$ $Ca$ $Br$ $Sr$ $I$ $Ba$ Atomic Mass $(g \cdot mol^{-1})$ $7$ $23$ $35.5$ $39$ $40$ $80$ $88$ $127$ $137$ Which of the following does not form a $Dobereiner's$ triad?