Given below are two statements: one is labell | vedclass

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(A) According to Gauss's Law,the net electric flux $\phi$ through any closed surface is given by $\phi = \frac{Q_{	ext{in}}}{\varepsilon_0}$,where $Q

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Both $A$ and $R$ are true and $R$ is the correct explanation of $A$

Vedclass · Answer

(A) According to Gauss's Law,the net electric flux $\phi$ through any closed surface is given by $\phi = \frac{Q_{	ext{in}}}{\varepsilon_0}$,where $Q_{	ext{in}}$ is the total charge enclosed by the surface.An electric dipole consists of two equal and opposite charges,$+q$ and $-q$. Therefore,the total charge of an electric dipole is $Q_{	ext{in}} = (+q) + (-q) = 0$.Since the total charge enclosed by the surface is zero,the net flux $\phi$ coming out of the surface is $\phi = \frac{0}{\varepsilon_0} = 0$.Thus,Assertion $A$ is true because the net charge of the dipole is zero,and Reason $R$ is true because it correctly defines the composition of an electric dipole,which serves as the explanation for why the net charge is zero.Therefore,both $A$ and $R$ are true and $R$ is the correct explanation of $A$.

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