Given below are two statements: Statement $I$: Each electron in $e_g$ orbitals destabilizes the orbitals by $+0.6\Delta_o$ and each electron in the $t_{2g}$ orbitals stabilizes the orbitals by $-0.4\Delta_o$ in an octahedral field on the basis of crystal field theory. Statement $II$: All the $d$-orbitals of the transition metals have the same energy in their free atomic state but when a complex is formed the ligands destroy the degeneracy of these orbitals on the basis of crystal field theory. In the light of the above statements, choose the correct answer from the options given below:

  • A
    Both Statement $I$ and Statement $II$ are correct
  • B
    Both Statement $I$ and Statement $II$ are incorrect
  • C
    Statement $I$ is correct but Statement $II$ is incorrect
  • D
    Statement $I$ is incorrect but Statement $II$ is correct

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Similar Questions

The hexaquo manganese $(II)$ ion contains five unpaired electrons,while the hexacyano manganese $(II)$ ion contains only one unpaired electron. Explain using Crystal Field Theory.

In the octahedral crystal field,the correct order of splitting for $I^{-}, H_2O, NH_3$ and $CN^{-}$ ligands is:

The values of the crystal field stabilization energies for a high spin $d^{6}$ metal ion in octahedral and tetrahedral fields,respectively,are :

For which of the following types of ions is the number of unpaired electrons in octahedral complexes fixed at the same number as in the free ion,no matter how weak or strong the crystal field is?

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The tetrahedral crystal field splitting energy is equal to ................. of the octahedral crystal field splitting energy.

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