Given below are two statements:Statement I: M | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The power dissipated in an $AC$ circuit is given by $P = V_{rms} I_{rms} \cos \phi$, where $\cos \phi$ is the power factor.For a series $LCR$ circ

Vedclass · Accepted Answer

Both Statement $I$ and Statement $II$ are true.

Vedclass · Answer

(C) The power dissipated in an $AC$ circuit is given by $P = V_{rms} I_{rms} \cos \phi$, where $\cos \phi$ is the power factor.For a series $LCR$ circuit, the impedance is $Z = \sqrt{R^2 + (X_L - X_C)^2}$.At resonance, $X_L = X_C$, which makes the impedance $Z$ minimum $(Z = R)$ and the phase difference $\phi = 0$. Thus, $\cos \phi = 1$, and power dissipation is maximum. Therefore, Statement $I$ is true.In a pure resistive circuit, the current and voltage are in the same phase $(\phi = 0)$, so $\cos \phi = 1$. This results in maximum power dissipation for a given voltage. Therefore, Statement $II$ is true.Hence, both statements are correct.

Similar Questions

In an $LCR$ series $AC$ circuit at resonance,the value of the power factor will be . . . . . . .

At what angular frequency $\omega$ does the following circuit consume maximum power? (in $rad/s$)

In the circuit shown in the figure,neglecting source resistance,the voltmeter and ammeter readings will respectively be:

$A$ series combination of a resistor of resistance $100\,\Omega$,an inductor of inductance $1\,H$,and a capacitor of capacitance $6.25\,\mu F$ is connected to an $AC$ source. The quality factor of the circuit will be $.............$.

In an $LCR$ series circuit,if the frequency is increased,the impedance of the circuit

Vedclass Test Series

Exam Paper Generator

Online Exam Module