Given below are two statements:
Statement $I$: $o$-Phenylenediamine can be synthesized from $o$-xylene using simpler reagents in the order: $i)$ Acidic $KMnO_4$, $ii)$ Ammonia, $iii)$ Bromine and alkali.
Statement $II$: Aniline can be converted into benzene using reagents in the order: $(i)$ Bromine-$H_2O$, $(ii)$ $NaNO_2 / HCl$ $(0-5^{\circ} C)$, $(iii)$ aq. $H_3PO_2$.
In the light of the above statements, choose the correct answer from the options given below.

  • A
    Both Statement $I$ and Statement $II$ are false
  • B
    Statement $I$ is true but Statement $II$ is false
  • C
    Both Statement $I$ and Statement $II$ are true
  • D
    Statement $I$ is false but Statement $II$ is true

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Similar Questions

Match the following:
List-$I$ (Amine)List-$II$ ($pK_b$ value)
$A$. $N,N$-Dimethylaniline$I$. $9.30$
$B$. Aniline$II$. $8.92$
$C$. $N$-Ethylethanamine$III$. $9.38$
$D$. $N$-Methylaniline$IV$. $3.00$

The correct answer is

What are $X$ and $Y$ respectively in the following set of reactions?

In a reaction of aniline,a coloured product $C$ was obtained as shown below:
$A$ $\xrightarrow{NaNO_2/HCl} B$ $\xrightarrow{N,N-dimethylaniline, \text{cold}} C$
The structure of $C$ would be:

Which of the following species would not be involved in the Hoffmann rearrangement shown below?

What is the product obtained when the product of alkaline hydrolysis of $C_2H_5 - N = C = O$ is reacted with $t$-butyl magnesium bromide?

Difficult
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