Given below are two statements:
Statement $I$: $F_2O < H_2O < Cl_2O$ is the correct trend in terms of bond angle.
Statement $II$: $SiF_4, SnF_4$ and $PbF_4$ are ionic in nature.
Statement $I$: $F_2O < H_2O < Cl_2O$ is the correct trend in terms of bond angle.
Statement $II$: $SiF_4, SnF_4$ and $PbF_4$ are ionic in nature.
- ABoth Statement $I$ and Statement $II$ are true
- BBoth Statement $I$ and Statement $II$ are false
- CStatement $I$ is true but Statement $II$ is false
- DStatement $I$ is false but Statement $II$ is true
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Similar Questions
Match the following molecules in Column $I$ with the number of lone pairs on their central atom in Column $II$.
Column $I$ (Molecules) Column $II$ (Number of lone pairs on central atom) $A. \ NH_3$ $1. \ \text{Two}$ $B. \ H_2O$ $2. \ \text{Three}$ $C. \ XeF_2$ $3. \ \text{Zero}$ $D. \ CH_4$ $4. \ \text{Four}$ $5. \ \text{One}$
| Column $I$ (Molecules) | Column $II$ (Number of lone pairs on central atom) |
|---|---|
| $A. \ NH_3$ | $1. \ \text{Two}$ |
| $B. \ H_2O$ | $2. \ \text{Three}$ |
| $C. \ XeF_2$ | $3. \ \text{Zero}$ |
| $D. \ CH_4$ | $4. \ \text{Four}$ |
| $5. \ \text{One}$ |
The formation of $PH_4^+$ is difficult compared to $NH_4^+$ because
The bonds present in $N_2O_{5(s)}$ is/are:
$I$. Ionic
$II$. Covalent
$III$. Coordinate
$I$. Ionic
$II$. Covalent
$III$. Coordinate
Medium
View Solution$NH_2^-$,$NH_3$ and $NH_4^+$ do not show similarity in the following:
Medium
View SolutionIn the formation of a molecule by atoms,which forces operate?
Difficult
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